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Q 3) A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its center of mass is K. If radius of the ball be R, then the fraction of total energy associated with its rotational energy will be AIPMT/NEET 2003 | C.O.M & Rotation Q 3 | If a body performs rotational kinetic motion as well as linear motion, then the total energy of body is equal to the sum of kinetic energy of rotational motion and kinetic energy of linear motion. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all the time, solutions are available in written format)j...

Q 2) A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of length L and height h. What is the speed of its centre of mass when the cylinder reaches its bottom ? AIPMT/NEET 2003 | C.O.M & Rotation Q 2 | In case of rolling motion of an object on an inclined plane along downward direction, gravitation potential energy loss by body will be equal to gain in its combined Kinetic energy since there is no work done by any torque of any external force as well as by any non conservative fo rce. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all ...

Q 1) A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity  ω  Two objects each of mass m are (attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by AI PMT/NEET 2003 | C.O.M & Rotation Q 1 | In the process of attaching masses on rotating circular ring there will be no external torque so Angular Momentum of system will remain conserved. If external torque about a axis is zero then angular momentum of the system about that axis will remains conserved. So if t axis = 0 Þ L axis = constant Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small chang...

Body A of mass 4m is moving with speed u collides with another body B of mass 2m , at rest . The collision is head on and elastic in nature . After the collision the fraction of energy lost by the colliding body A is Neet 2019 | W.P.E Q 5 |I told you earlier in qus   of year 2010 , 2011 , 2012 ,2016 & 2018. If you haven’t subscribed my channel then do it now and don’t miss any important thing about Neet. In case of collision the two bodies of masses m1 and m2 are moving along a line with velocities u1 and u2 respectively, u1 should be greater then u2 for two bodies to collide. As the velocity of m1 (u1) is greater than that of m2 (u2), there will be a deformation in the bodies. This deformation continues till they acquire same velocity. Now a question arises, that why will they acquire same velocity. The velocity of the front body m2 (which was slower initially) will gradually increase, and the velocity of the rear body m1 (which was faster initially) will gradually decre...

A mass m is attached  to a thin wire and whirled in a vertical circle . The wire is most likely to break when AIPMT/NEET 2019 | W.P.E Q 4 | In this case Mechanical energy will remain conserved because tension will always act perpendicular to displacement i.e direction of velocity so its work done will be zero. Gravity is a conservative force and there is no non-conservative force present . Conservation of Mechanical Energy The work-energy theorem, shows that the change D KE in a body’s kinetic energy is equal to the net work done on it :   D KE = Wnet Consider separately the work Wc done by conservative force and the work Wnc done by nonconservative forces. Then D KE = Wc+ Wnc We’ve defined the change in potential energy D U as the negative of the work done by conservative forces. So we can write D KE = – D U + Wnc or D KE + D U = Wnc We define the sum of the kinetic and potential energy as the mechanical energy. Then Equation shownthat the change in mechanical en...

When a block of mass M is suspended by a long wire of length L , the length of the wire become ( L + l ) . The elastics potenital energy stored in the extended wire is AIPMT/NEET 2019 | W.P.E Q 3 | You may consider this qus in Elasticity or Properties of matter but I think since it includes discussion of potential energy . Its better to discuss it here . All we need is the formula of Elastic potential energy. We can derive it also but I don’t think we need that here. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all the time, solutions are available in written format)just...

A force F = 20 + 10y acts on a particle in y- direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is AIPMT/NEET 2019 | W.P.E Q 2 | We had seen same qus in year 2005 and 2011( graph based ) so once again I advice you all please try to solve old Neet qus and if you are still not following my channel then please like , share and subscribe right now. Relation between force v/s distance is given , from which we can understand , the force is variable. When Force is variable (either magnitude or direction) : If the force applied on a body is changing its direction or magnitude or both , the force is said to be variable. dW = Sd·F r r Þ W = ò r Sd·F r ( F r cannot come out of integral since it is varying) = Area under force v/s distance curve. Simple calculation in this qus as compared to previous qus.   Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. ...

The work done to raise a mass m from the surface of Earth to a height h, which is equal to the radius of the Earth is AIPMT/NEET 2019 | W.P.E Q 1 | Here we need to use the advance level formula of potential energy i.e from Gravitation chapter of potential energy. Then we are going to apply relation between work done by external agent , work done by conservative force and potential energy. If you don’t the advance relation then this qus can be tough for you. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all the time, solutions are available in written format)just a click a...

A body initially at rest and sliding along a frictionless track from a height h (as shown in the figure) just completes a vertical circle of diameter  AB = D . The height h is equal to Neet 2018 | W P E Q 2 | In case of vertical circular motion , we require a minimum velocity at lowest position of circle to complete the circle. For any value of velocity greater than this , particle can easily complete its circular motion and at the minimum value of this velocity , normal force ( in other cases it could be tension force ) becomes zero .Even at zero normal reaction force ( in other cases it could be tension force ) particle will not fall towards the centre since it will has some velocity So it will cross that weightlessness  . you must know about this if you had subscribed my channel because I already posted these conditions in my twisted qus videos with solution of Q 3 Aipmt/Neet 2004 , year 2008 and year 2016 also. In this case Mechanical energy will remain conserved becaus...

Q. A moving block having mass  m , collides with another stationary block having mass  4 m . The lighter block comes to rest after collision. When the initial velocity of the lighter block is  v , then the value of coefficient of restitution (e) will be Neet 2018 | W.P.E Q 1 | I told you earlier in qus  of year 2010 , 2011 , 2012 & 2016. If you haven’t subscribed my channel then do it now and don’t miss any important thing about Neet. In case of collision the two bodies of masses m1 and m2 are moving along a line with velocities u1 and u2 respectively, u1 should be greater then u2 for two bodies to collide. As the velocity of m1 (u1) is greater than that of m2 (u2), there will be a deformation in the bodies. This deformation continues till they acquire same velocity. Now a question arises, that why will they acquire same velocity. The velocity of the front body m2 (which was slower initially) will gradually increase, and the velocity of the rear body m1 (wh...

Consider a drop of rain water having mass  1 g  falling from a height of  1 km . It hits the ground with a speed of  50m/s . Take 'g' constant with a value  10m/s2 . The work done by the (i) gravitational force and the (ii) resistive force of air is : Neet 2017 | W.P.E Q 1 | Two qus are asked in a single one but still qus is of average level. There are multiple forces involve so we will apply work energy theorem and work done by gravity i.e the conservative force. Practically it’s the non-conservative force i.e work done by resistance force that needs to be calculate. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or...

A particle moves from a point vector (-2i+5j) N is (4j+3k) when a force of vector (4i+3j) N is applied. How much work has been done by the force ? Neet 2016 W P E Q 6 Practically nothing to do much in this qus . Force is constant, info of initial and final positions are given. All we need to find out the dot product of force and displacement .  Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all the time, solutions are available in written format)just a click away on questionnahibanta.blogspot.com   If you have anything to say/discuss ,feel free to contact Emai...

Q. Two identical balls A and B having velocities of  0.5 m / s − 1 and  − 0.3 m / s − 1 respectively collide elastically in one dimension. The velocities of  B and  A  after the collision respectively will be  Neet 2016 W P E Q 5 I told you earlier in qus  of year 2010 , 2011 & 2012. If you haven’t subscribed my channel then do it now and don’t miss any important thing about Neet. In case of collision the two bodies of masses m1 and m2 are moving along a line with velocities u1 and u2 respectively, u1 should be greater then u2 for two bodies to collide. As the velocity of m1 (u1) is greater than that of m2 (u2), there will be a deformation in the bodies. This deformation continues till they acquire same velocity. Now a question arises, that why will they acquire same velocity. The velocity of the front body m2 (which was slower initially) will gradually increase, and the velocity of the rear body m1 (which was faster initially) will gradual...