A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes ...

A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three pieces. Two pieces, each of mass (m) move perpendicular to each other with equal speeds (v). The total kinetic energy generated due to explosion is (a) mv2 (b) 3/2mv2 (c) 2mv2 (d) 4mv2

NEET 2014 | W.P.E Q 1 |We had seen similar qus in year 2005 where we had to find kinetic energy of the third particle .Here in this qus first we have to understand that in an explosion , external force is zero so linear momentum of system will remain conserved. With the help of this , we can find momentum of third mass  . Second thing is the relation between kinetic energy and linear momentum. Kinetic energy of explosion will be the sum of kinetic energies of all three particles

“ Explosion” which means external force is zero on system which means in other words linear momentum of system will remain conserved the linear momentum of a system remains constant (in magnitude and direction), if the external forces acting on the system add up to zero. This is known as the principle of conservation of linear momentum.
Let as see a simple example of a bomb explosion.
Consider a bomb placed on a horizontal surface which suddenly explodes into two parts of masses m1 and m2 .The forces that are responsible for the explosion are internal. As there is no external force on the system, momentum of system remains conserved. The initial momentum of the system is zero, Thus the final momentum of the system must also be zero.

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