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Q 3) A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its center of mass is K. If radius of the ball be R, then the fraction of total energy associated with its rotational energy will be AIPMT/NEET 2003 | C.O.M & Rotation Q 3 | If a body performs rotational kinetic motion as well as linear motion, then the total energy of body is equal to the sum of kinetic energy of rotational motion and kinetic energy of linear motion. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all the time, solutions are available in written format)j...

Q 2) A solid cylinder of mass M and radius R rolls without slipping down an inclined plane of length L and height h. What is the speed of its centre of mass when the cylinder reaches its bottom ? AIPMT/NEET 2003 | C.O.M & Rotation Q 2 | In case of rolling motion of an object on an inclined plane along downward direction, gravitation potential energy loss by body will be equal to gain in its combined Kinetic energy since there is no work done by any torque of any external force as well as by any non conservative fo rce. Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small change in data given or language. Check out text solution( No need to run videos all ...

Q 1) A thin circular ring of mass M and radius r is rotating about its axis with constant angular velocity  ω  Two objects each of mass m are (attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity given by AI PMT/NEET 2003 | C.O.M & Rotation Q 1 | In the process of attaching masses on rotating circular ring there will be no external torque so Angular Momentum of system will remain conserved. If external torque about a axis is zero then angular momentum of the system about that axis will remains conserved. So if t axis = 0 Þ L axis = constant Don't forget to LIKE , SHARE & SUBSCRIBE my Channel. Please Press BELL icon to receive latest updates. Don't miss Hint based videos / concept related videos/ twisted qus videos available only on this channel , from which you can learn the most solid framework of problem solving/ clarity in application of different concepts/ formation of other problems with a small chang...

Body A of mass 4m is moving with speed u collides with another body B of mass 2m , at rest . The collision is head on and elastic in nature . After the collision the fraction of energy lost by the colliding body A is Neet 2019 | W.P.E Q 5 |I told you earlier in qus   of year 2010 , 2011 , 2012 ,2016 & 2018. If you haven’t subscribed my channel then do it now and don’t miss any important thing about Neet. In case of collision the two bodies of masses m1 and m2 are moving along a line with velocities u1 and u2 respectively, u1 should be greater then u2 for two bodies to collide. As the velocity of m1 (u1) is greater than that of m2 (u2), there will be a deformation in the bodies. This deformation continues till they acquire same velocity. Now a question arises, that why will they acquire same velocity. The velocity of the front body m2 (which was slower initially) will gradually increase, and the velocity of the rear body m1 (which was faster initially) will gradually decre...

A mass m is attached  to a thin wire and whirled in a vertical circle . The wire is most likely to break when AIPMT/NEET 2019 | W.P.E Q 4 | In this case Mechanical energy will remain conserved because tension will always act perpendicular to displacement i.e direction of velocity so its work done will be zero. Gravity is a conservative force and there is no non-conservative force present . Conservation of Mechanical Energy The work-energy theorem, shows that the change D KE in a body’s kinetic energy is equal to the net work done on it :   D KE = Wnet Consider separately the work Wc done by conservative force and the work Wnc done by nonconservative forces. Then D KE = Wc+ Wnc We’ve defined the change in potential energy D U as the negative of the work done by conservative forces. So we can write D KE = – D U + Wnc or D KE + D U = Wnc We define the sum of the kinetic and potential energy as the mechanical energy. Then Equation shownthat the change in mechanical en...